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# Horizontal Launch off a Cliff

Q: An object is launched horizontally off a cliff with a velocity of 14 m/s.
a) How long will it be in the air for?
b) How far, horizontally, will the ball move before hitting the ground?

A: The keys to this question is that horizontal velocity is constant, and initially the vertical velocity is zero.

Throughout the the entire time that the ball is falling, horizontal velocity is constant, $V_x=14 m/s$ .
Initially, it is not moving vertically, so the vertical velocity is zero.

For a) Find the time it takes to drop 25 meters in the vertical, with an acceleration of $a=-9.8 m/s^2$, due to gravity.

You can then use this time to solve for the horizontal distance. See the image for calculations and diagrams.